[Solved] Consider this Menu class snippet:class Menu { Map items = new HashMap();... } }What will happen if addItem is called twice with the same dish name but different prices? | LLD

LLD - Design — Food Delivery System

Consider this Menu class snippet:

class Menu {
  Map items = new HashMap<>();
  void addItem(String name, double price) {
    items.putIfAbsent(name, price);
  }
}

What will happen if addItem is called twice with the same dish name but different prices?

AThe price is updated to the second inserted price

BThe price remains the first inserted price; second call is ignored

CAn exception is thrown on the second call

DBoth prices are stored as separate entries

Step-by-Step Solution

Solution:

Step 1: Understand putIfAbsent behavior
putIfAbsent inserts the key-value only if the key is not already present.
Step 2: Effect of calling addItem twice with same name
The first call inserts the price; the second call does nothing since key exists.
Final Answer:
The price remains the first inserted price; second call is ignored -> Option B
Quick Check:
putIfAbsent ignores duplicate keys [OK]

Quick Trick: putIfAbsent prevents overwriting existing keys [OK]

Common Mistakes:

MISTAKES

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