[Solved] What will be the output of this pseudocode snippet for assigning agents?agents = [Agent1(busy), Agent2(free), Agent3(free)]AssignAgent(order): for agent in agents: if agent.status == "free":... | LLD

LLD - Design — Food Delivery System

What will be the output of this pseudocode snippet for assigning agents?

agents = [Agent1(busy), Agent2(free), Agent3(free)]
AssignAgent(order):
   for agent in agents:
     if agent.status == "free":
       return agent.name
   return "No agent"
print(AssignAgent(order))

AAgent2

BAgent1

CNo agent

DAgent3

Step-by-Step Solution

Solution:

Step 1: Iterate over agents in order
Agent1 is busy, so skipped. Agent2 is free, so returned immediately.
Step 2: Confirm output
Function returns Agent2's name on first free agent found.
Final Answer:
Agent2 -> Option A
Quick Check:
First free agent = Agent2 [OK]

Quick Trick: Returns first free agent found in list order [OK]

Common Mistakes:

Returning busy agent
Returning last free agent instead of first
Returning "No agent" incorrectly

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What will be the output of this pseudocode snippet for assigning agents?

Step 1: Iterate over agents in order

Step 2: Confirm output

Final Answer:

Quick Check:

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