[Solved] Consider this pseudocode for assigning an agent:for agent in agents: if agent.status == 'free' and distance(agent, order) < min_distance:... | LLD

LLD - Design — Food Delivery System

Consider this pseudocode for assigning an agent:
for agent in agents: if agent.status == 'free' and distance(agent, order) < min_distance: min_distance = distance(agent, order) assigned_agent = agent return assigned_agent
What will this code return if all agents are busy?

AThe closest free agent

BNone or null

CThe first agent in the list

DAn error due to undefined variable

Step-by-Step Solution

Solution:

Step 1: Check variable initializations
The code does not initialize assigned_agent or min_distance before the loop.
Step 2: Trace execution when all agents are busy
The if condition's first part (agent.status == 'free') fails for all agents, so due to short-circuit evaluation of 'and', the second part (distance < min_distance) is never evaluated. The loop ends without ever setting assigned_agent. Returning an uninitialized assigned_agent causes an error due to undefined variable.
Final Answer:
An error due to undefined variable -> Option D
Quick Check:
No initialization + all busy = undefined variable error [OK]

Quick Trick: No variable initialization leads to undefined variable error [OK]

Common Mistakes:

Thinking assigned_agent defaults to None or null
Assuming it returns the first agent regardless of status
Believing the code handles no free agents gracefully

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Consider this pseudocode for assigning an agent:

Step 1: Check variable initializations

Step 2: Trace execution when all agents are busy

Final Answer:

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