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Given the following pseudo-code for an iterator over a list of integers:

medium📝 Analysis Q4 of 15
LLD - Behavioral Design Patterns — Part 1

Given the following pseudo-code for an iterator over a list of integers:

iterator = list.getIterator()
sum = 0
while (iterator.hasNext()) {
sum += iterator.next()
}
print(sum)

What will be the output if the list contains [1, 2, 3, 4]?

A10
B24
C1234
DError due to missing initialization
Step-by-Step Solution
Solution:
  1. Step 1: Understand the iteration and summation

    The code sums all elements by iterating over the list: 1 + 2 + 3 + 4.
  2. Step 2: Calculate the sum

    Sum = 1 + 2 + 3 + 4 = 10.
  3. Final Answer:

    10 -> Option A
  4. Quick Check:

    Sum of list elements = 10 [OK]
Quick Trick: Sum elements by adding each next() value [OK]
Common Mistakes:
MISTAKES
  • Concatenating numbers instead of summing
  • Assuming error due to iterator usage

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