[Solved] What will be the output of this code snippet?class Elevator: def __init__(self): self.current_floor = 0 def move_up(self): self.current_floor += 1 el = Elevator() el.move_up() el.move_up() print(el.... | LLD

LLD - Design — Elevator System

What will be the output of this code snippet?

class Elevator:
    def __init__(self):
        self.current_floor = 0
    def move_up(self):
        self.current_floor += 1

el = Elevator()
el.move_up()
el.move_up()
print(el.current_floor)

A0

B2

C1

DError: current_floor undefined

Step-by-Step Solution

Solution:

Step 1: Initial value of current_floor
Elevator starts at floor 0.
Step 2: Two calls to move_up increment floor by 1 each
After two calls, current_floor = 0 + 1 + 1 = 2.
Final Answer:
2 -> Option B
Quick Check:
Increment current_floor twice = 2 [OK]

Quick Trick: Each move_up adds 1 to current_floor [OK]

Common Mistakes:

MISTAKES

Forgetting increments
Assuming initial floor is 1
Confusing method call effects

Master "Design — Elevator System" in LLD

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Arch Try Challenge Design Recall Scale

More LLD Quizzes

What will be the output of this code snippet?

Step 1: Initial value of current_floor

Step 2: Two calls to move_up increment floor by 1 each

Final Answer:

Quick Check:

Want More Practice?