How can you combine dmesg with awk to print only the message text from kernel logs (excluding the timestamp)?

hard📝 Application Q9 of 15

Linux CLI - System Administration

How can you combine dmesg with awk to print only the message text from kernel logs (excluding the timestamp)?

Asudo dmesg | awk '{$1=""; print $0}'

Bsudo dmesg | awk '{print $1}'

Csudo dmesg | awk '{print $1, $2}'

Dsudo dmesg | awk '{print $2, $3}'

Step-by-Step Solution

Solution:

Step 1: Understand dmesg output format
dmesg lines start with a timestamp in brackets, e.g. [12345.678].
Step 2: Use awk to remove timestamp and print message
Setting $1="" removes the first field (timestamp), then printing $0 prints the rest (message text).
Step 3: Check other options
Options printing only $1 or $1 and $2 do not correctly print the full message text without the timestamp.
Final Answer:
sudo dmesg | awk '{$1=""; print $0}' -> Option A
Quick Check:
Remove timestamp field, print message text with awk [OK]

Quick Trick: Use awk '{$1=""; print $0}' to skip first field [OK]

Common Mistakes:

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