Linux CLI - Text Processing
Given a CSV file with columns: name,age,score, how to print names of people with score above 80 using awk?
Given a CSV file with columns: name,age,score, how to print names of people with score above 80 using awk?
hard📝 Application Q9 of 15
Step-by-Step Solution
Solution:
Step 1: Set field separator to comma
Use -F',' to split CSV fields correctly.Step 2: Filter rows with score > 80 and print name
Score is third column ($3), name is first ($1), so condition '$3 > 80 {print $1}' works.Final Answer:
awk -F',' '$3 > 80 {print $1}' file.csv -> Option BQuick Check:
Filter by $3 > 80, print $1 = B [OK]
Quick Trick: Use -F',' for CSV and filter with condition in awk [OK]
Common Mistakes:
- Mixing up field numbers
- Not setting field separator
- Printing wrong column
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