You want to find how many lines in server.log contain the word timeout ignoring case, and display only the count. Which command should you use?

hard📝 Application Q15 of 15

Linux CLI - Text Processing

You want to find how many lines in server.log contain the word timeout ignoring case, and display only the count. Which command should you use?

Agrep -i -c timeout server.log

Bgrep -i timeout server.log

Cgrep timeout -i -c server.log

Dgrep -c timeout server.log

Step-by-Step Solution

Solution:

Step 1: Identify options needed
You need to ignore case (-i) and count matching lines (-c).
Step 2: Check correct option order
Options can be combined as -i -c or -c -i. grep -i -c timeout server.log uses both correctly before pattern and file.
Step 3: Analyze other options
grep -c timeout server.log lacks case insensitivity. grep -i timeout server.log shows matches but not count. grep timeout -i -c server.log has incorrect argument order (pattern before options).
Final Answer:
grep -i -c timeout server.log -> Option A
Quick Check:
Use -i and -c together for case-insensitive count [OK]

Quick Trick: Combine -i and -c to count ignoring case [OK]

Common Mistakes:

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