[Solved] What will be the output of the following Bash commands?count=3 while [ $count -gt 0 ]; do echo $count ((count--)) done | Linux CLI

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What will be the output of the following Bash commands?

count=3
while [ $count -gt 0 ]; do
  echo $count
  ((count--))
done

A3 2 1

B1 2 3

C3 2 1 0

D0 1 2 3

Step-by-Step Solution

Solution:

Step 1: Understand the loop and condition
The loop starts with count=3 and runs while count is greater than 0. It prints count then decreases it by 1 each time.
Step 2: Trace the output values
First iteration: prints 3, count becomes 2
Second: prints 2, count becomes 1
Third: prints 1, count becomes 0
Loop ends because 0 is not greater than 0.
Final Answer:
3 2 1 -> Option A
Quick Check:
Loop output sequence = 3 2 1 [OK]

Quick Trick: Loops run while condition is true; count decreases each time [OK]

Common Mistakes:

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