Solution:Step 1: Understand lambda function behaviorThe lambda multiplies input by 3, so input 4 becomes 4 * 3 = 12.Step 2: Apply invoke methodCalling invoke(4) runs the lambda and returns 12.Final Answer:12 -> Option BQuick Check:RunnableLambda invoke(4) = 12 [OK]

[Solved] Given this code:lambda_runner = RunnableLambda(lambda x: x * 3) output = lambda_runner.invoke(4)What is the value of output? | LangChain

LangChain - Chains and LCEL

Given this code:

lambda_runner = RunnableLambda(lambda x: x * 3)
output = lambda_runner.invoke(4)

What is the value of output?

A4

B12

CError: lambda not callable

D7

Step-by-Step Solution

Solution:

Step 1: Understand lambda function behavior
The lambda multiplies input by 3, so input 4 becomes 4 * 3 = 12.
Step 2: Apply invoke method
Calling invoke(4) runs the lambda and returns 12.
Final Answer:
12 -> Option B
Quick Check:
RunnableLambda invoke(4) = 12 [OK]

Quick Trick: Invoke runs lambda; 4 * 3 = 12 [OK]

Common Mistakes:

Confusing multiplication with addition
Expecting input unchanged
Assuming lambda is not callable

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Given this code:

Step 1: Understand lambda function behavior

Step 2: Apply invoke method

Final Answer:

Quick Check:

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