[Solved] Given the following code snippet in LangChain:chain1 = SomeChain() chain2 = AnotherChain() result = chain1 | chain2 output = result.run('input data')What happens when result.... | LangChain

LangChain - Chains and LCEL

Given the following code snippet in LangChain:

chain1 = SomeChain()
chain2 = AnotherChain()
result = chain1 | chain2
output = result.run('input data')

What happens when result.run('input data') is called?

AOnly chain1 processes the input data; chain2 is ignored

BThe input data flows through chain1, then its output flows into chain2, producing final output

CThe input data is processed by chain2 first, then chain1

DAn error occurs because pipe operator cannot be used this way

Step-by-Step Solution

Solution:

Step 1: Understand pipe operator chaining behavior
The pipe operator connects chains so output of the first chain becomes input to the second.
Step 2: Trace data flow in the code
Calling result.run('input data') sends 'input data' to chain1, then its output flows into chain2, producing the final output.
Final Answer:
The input data flows through chain1, then its output flows into chain2, producing final output -> Option B
Quick Check:
Pipe operator = sequential chain flow [OK]

Quick Trick: Pipe operator sends output of first chain to next [OK]

Common Mistakes:

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