Bird
0
0

What error is most likely raised when JsonOutputParser.parse() is called with a malformed JSON string such as '{name: Alice, age: 30}'?

medium📝 component behavior Q5 of 15
LangChain - Output Parsers
What error is most likely raised when JsonOutputParser.parse() is called with a malformed JSON string such as '{name: Alice, age: 30}'?
AValueError because the JSON keys are missing quotes
BTypeError because the input is not a dictionary
Cjson.decoder.JSONDecodeError due to invalid JSON syntax
DKeyError because 'name' key is not found
Step-by-Step Solution
Solution:
  1. Step 1: Identify the input problem

    The JSON string lacks quotes around keys, making it invalid JSON syntax.
  2. Step 2: Understand parser behavior

    JsonOutputParser uses Python's JSON decoder which raises JSONDecodeError on invalid syntax.
  3. Step 3: Evaluate options

    json.decoder.JSONDecodeError due to invalid JSON syntax correctly identifies the error. Options B, C, and D are incorrect because the input is a string (not a dict), and the error is specifically JSONDecodeError.
  4. Final Answer:

    json.decoder.JSONDecodeError due to invalid JSON syntax -> Option C
  5. Quick Check:

    Malformed JSON triggers JSONDecodeError in parsing. [OK]
Quick Trick: Malformed JSON strings cause JSONDecodeError. [OK]
Common Mistakes:
  • Confusing JSONDecodeError with TypeError or ValueError.
  • Assuming missing quotes cause KeyError.
  • Thinking parse accepts invalid JSON.

Want More Practice?

15+ quiz questions · All difficulty levels · Free

Free Signup - Practice All Questions
More LangChain Quizzes