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You want to design a Kubernetes HA cluster that can tolerate failure of two control plane nodes. How many control plane nodes should you deploy at minimum?

hard📝 Application Q8 of 15
Kubernetes - Production Best Practices
You want to design a Kubernetes HA cluster that can tolerate failure of two control plane nodes. How many control plane nodes should you deploy at minimum?
A4
B5
C2
D3
Step-by-Step Solution
Solution:
  1. Step 1: Understand quorum in etcd for HA

    etcd requires majority quorum to operate; to tolerate 2 failures, majority must remain.
  2. Step 2: Calculate minimum nodes for 2 node failure tolerance

    Minimum nodes = 2 * failures + 1 = 2*2 + 1 = 5 nodes.
  3. Final Answer:

    5 -> Option B
  4. Quick Check:

    Nodes needed = 2*failures + 1 = 5 [OK]
Quick Trick: Use formula 2*faults+1 for control plane nodes [OK]
Common Mistakes:
  • Choosing 3 nodes which tolerate only 1 failure
  • Assuming 2 nodes can tolerate 2 failures
  • Picking 4 nodes which is insufficient for 2 failures

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