[Solved] Given the function below, how can you call it by passing an existing IntArray named numbers?fun printNumbers(vararg nums: Int) { for (num in nums) print("$num ") } | Kotlin

Kotlin - Functions

Given the function below, how can you call it by passing an existing IntArray named numbers?

fun printNumbers(vararg nums: Int) {
    for (num in nums) print("$num ")
}

AprintNumbers(numbers)

BprintNumbers(*numbers)

CprintNumbers(&numbers)

DprintNumbers(numbers.toList())

Step-by-Step Solution

Solution:

Step 1: Understand how to pass arrays to vararg
To pass an existing array to a vararg parameter, use the spread operator * before the array.
Step 2: Check each option
printNumbers(*numbers) uses the spread operator correctly. printNumbers(numbers) passes the array as a single argument. printNumbers(&numbers) uses invalid syntax. printNumbers(numbers.toList()) converts to list, which is not accepted by vararg of Int.
Final Answer:
printNumbers(*numbers) -> Option B
Quick Check:
Use * to spread array into vararg [OK]

Quick Trick: Use * to spread array when passing to vararg [OK]

Common Mistakes:

MISTAKES

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Given the function below, how can you call it by passing an existing IntArray named numbers?