[Solved] What is the issue with this Kotlin function?fun displayLength(obj: Any) { if (obj is String) { println(obj.length) } else { println(obj.length) } } | Kotlin

Kotlin - Variables and Type System

What is the issue with this Kotlin function?

fun displayLength(obj: Any) {
    if (obj is String) {
        println(obj.length)
    } else {
        println(obj.length)
    }
}

AFunction should return an Int instead of printing

BMissing semicolon after println statements

CIncorrect use of 'is' operator syntax

DAccessing 'length' on 'obj' in else block without confirming it's a String

Step-by-Step Solution

Solution:

Step 1: Review type checking
The is operator confirms obj is a String only in the if block.
Step 2: Identify problem in else block
In else, obj might not be a String, so accessing length causes error.
Final Answer:
Accessing 'length' on 'obj' in else block without confirming it's a String -> Option D
Quick Check:
Only access String properties after confirming type [OK]

Quick Trick: Check type before accessing properties [OK]

Common Mistakes:

MISTAKES

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