[Solved] What will be the output of this Kotlin code?fun test(obj: Any) { when (obj) { is String -> println(obj.length) is Int -> println(obj + 1) else -> println("Unknown") } } test("Hello") test(5) test(3.... | Kotlin

Kotlin - Control Flow as Expressions

What will be the output of this Kotlin code?

fun test(obj: Any) {
    when (obj) {
        is String -> println(obj.length)
        is Int -> println(obj + 1)
        else -> println("Unknown")
    }
}

test("Hello")
test(5)
test(3.14)

A5 6 7

B5 6 Unknown

CHello 6 Unknown

D5 5 Unknown

Step-by-Step Solution

Solution:

Step 1: Analyze each call
For test("Hello"), obj is String, so prints length 5.
For test(5), obj is Int, so prints 5 + 1 = 6.
For test(3.14), no matching type, prints "Unknown".
Step 2: Confirm output lines
Outputs are:
5
6
Unknown
Final Answer:
5 6 Unknown -> Option B
Quick Check:
Smart cast uses type to choose output [OK]

Quick Trick: Match type in when to get output [OK]

Common Mistakes:

MISTAKES

Confusing string length with string itself
Adding 1 to string instead of int
Expecting default else to print number

Master "Control Flow as Expressions" in Kotlin

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More Kotlin Quizzes

What will be the output of this Kotlin code?

Step 1: Analyze each call

Step 2: Confirm output lines

Final Answer:

Quick Check:

Want More Practice?