[Solved] Identify the error in this Kotlin code snippet:for (i in 1..5) if (i in 3..1) println(i) — Ans: No error, code runs fine | Kotlin

Kotlin - Operators and Expressions

Identify the error in this Kotlin code snippet:

for (i in 1..5)
    if (i in 3..1) println(i)

AThe for loop syntax is incorrect

BThe range 3..1 is invalid because start is greater than end

CNo error, code runs fine

DThe if condition should use 'not in' instead of 'in'

Step-by-Step Solution

Solution:

Step 1: Analyze the range 3..1
In Kotlin, a range with start greater than end (3..1) creates an empty range, which is valid.
Step 2: Verify code execution
The for loop runs for i=1 to 5, but i in 3..1 is always false for any i, so nothing prints. No syntax or runtime errors occur.
Final Answer:
No error, code runs fine -> Option C
Quick Check:
Empty ranges (start > end) are valid in Kotlin [OK]

Quick Trick: Ranges with start > end are empty but valid [OK]

Common Mistakes:

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