[Solved] Identify the error in this Kotlin script file example.kts: val name = "Alice" println(Name) — Ans: Variable 'Name' is not defined (case sensitive) | Kotlin

Kotlin - Basics and JVM Runtime

Identify the error in this Kotlin script file example.kts:

val name = "Alice"
println(Name)

AScript files cannot use println

BVariable 'Name' is not defined (case sensitive)

CMissing semicolon after println statement

DString literals must use single quotes

Step-by-Step Solution

Solution:

Step 1: Check variable usage
Variable declared as 'name' but used as 'Name' which differs in case.
Step 2: Understand Kotlin case sensitivity
Kotlin variables are case sensitive, so 'Name' is undefined causing error.
Final Answer:
Variable 'Name' is not defined (case sensitive) -> Option B
Quick Check:
Variable names are case sensitive [OK]

Quick Trick: Check variable name case carefully [OK]

Common Mistakes:

MISTAKES

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