[Solved] Why does this Kotlin code fail to compile to JVM bytecode?fun main() { val list = listOf(1, 2, 3) list[0] = 10 } | Kotlin

Kotlin - Basics and JVM Runtime

Why does this Kotlin code fail to compile to JVM bytecode?

fun main() { val list = listOf(1, 2, 3) list[0] = 10 }

AList is immutable, cannot assign to index

BSyntax error in list declaration

CJVM does not support lists

DMissing semicolon causes error

Step-by-Step Solution

Solution:

Step 1: Understand listOf behavior
listOf creates an immutable list; elements cannot be changed.
Step 2: Identify assignment error
Trying to assign to list[0] causes a compile-time error due to immutability.
Final Answer:
List is immutable, cannot assign to index -> Option A
Quick Check:
Immutable list disallows element assignment [OK]

Quick Trick: listOf creates immutable lists, use mutableListOf to modify [OK]

Common Mistakes:

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