You want to print all odd numbers from 15 down to 1 using a Kotlin for loop with downTo and step, without using an if statement. Which code snippet correctly does this?

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Kotlin - Loops and Ranges

You want to print all odd numbers from 15 down to 1 using a Kotlin for loop with downTo and step, without using an if statement. Which code snippet correctly does this?

Afor (i in 15 downTo 1 step 2) { println(i) }

Bfor (i in 15 downTo 1 step 1) { if (i % 2 == 1) println(i) }

Cfor (i in 15 downTo 1 step 3) { println(i) }

Dfor (i in 14 downTo 1 step 2) { println(i) }

Step-by-Step Solution

Solution:

Step 1: Understand the goal
We want to print odd numbers from 15 down to 1. Starting at 15 (which is odd) and stepping by 2 will print all odd numbers downwards.
Step 2: Evaluate options
for (i in 15 downTo 1 step 2) { println(i) } starts at 15 and steps by 2 down to 1, printing 15, 13, 11, ..., 1. for (i in 15 downTo 1 step 1) { if (i % 2 == 1) println(i) } uses step 1 with an if filter (disallowed). for (i in 15 downTo 1 step 3) { println(i) } steps by 3, skipping some odds. for (i in 14 downTo 1 step 2) { println(i) } starts at 14 (even), printing evens.
Final Answer:
for (i in 15 downTo 1 step 2) { println(i) } -> Option A
Quick Check:
Start odd, step 2 downTo 1 = odd numbers [OK]

Quick Trick: Start at odd number, step 2 downTo 1 for odd numbers [OK]

Common Mistakes:

MISTAKES

Starting at even number when printing odds
Using wrong step size
Filtering inside loop instead of stepping

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More Kotlin Quizzes

You want to print all odd numbers from 15 down to 1 using a Kotlin for loop with downTo and step, without using an if statement. Which code snippet correctly does this?

Step 1: Understand the goal

Step 2: Evaluate options

Final Answer:

Quick Check:

Want More Practice?