Kotlin - Operators and Expressions
Which of the following Kotlin expressions is syntactically correct to check referential equality?
Which of the following Kotlin expressions is syntactically correct to check referential equality?
easy📝 Syntax Q3 of 15
Step-by-Step Solution
Solution:
Step 1: Review Kotlin equality syntax
Referential equality in Kotlin is checked using===. This operator is valid syntax.Step 2: Identify invalid or incorrect syntax
a == bchecks structural equality,a = bis assignment, anda === bis valid syntax.Final Answer:
a === bis correct for referential equality -> Option BQuick Check:
Referential equality syntax = === = a === b [OK]
Quick Trick: Referential equality uses ===, not == or = [OK]
Common Mistakes:
MISTAKES- Using single = instead of == or ===
- Typing === which is invalid
- Confusing == with === for reference check
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