[Solved] Given this Kafka event stream, what will the consumer state be after processing all events?events = [ {"type": "create", "id": 1, "value": 10}, {"type": "update", "id": 1, "value": 20}, {"type":... | Kafka

Kafka - Event-Driven Architecture

Given this Kafka event stream, what will the consumer state be after processing all events?

events = [
  {"type": "create", "id": 1, "value": 10},
  {"type": "update", "id": 1, "value": 20},
  {"type": "create", "id": 2, "value": 5},
  {"type": "delete", "id": 1}
]

state = {}
for event in events:
    if event["type"] == "create" or event["type"] == "update":
        state[event["id"]] = event["value"]
    elif event["type"] == "delete":
        state.pop(event["id"], None)

print(state)

A{}

B{"1": 20, "2": 5}

C{"1": 10, "2": 5}

D{"2": 5}

Step-by-Step Solution

Solution:

Step 1: Process each event in order
First create id 1 with value 10, then update id 1 to 20, create id 2 with 5, then delete id 1.
Step 2: Determine final state
After deletion, id 1 is removed, only id 2 with value 5 remains.
Final Answer:
{"2": 5} -> Option D
Quick Check:
Delete removes id 1, only id 2 left [OK]

Quick Trick: Track events step-by-step to update state correctly [OK]

Common Mistakes:

MISTAKES

Forgetting the delete event removes id 1
Confusing update with create
Assuming old values remain after update

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More Kafka Quizzes

Given this Kafka event stream, what will the consumer state be after processing all events?

Step 1: Process each event in order

Step 2: Determine final state

Final Answer:

Quick Check:

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