[Solved] Given this Kafka Streams session window configuration:stream.groupByKey() .windowedBy(SessionWindows.with(Duration.ofSeconds(4))) .... | Kafka

Kafka - Streams

Given this Kafka Streams session window configuration:

stream.groupByKey()
  .windowedBy(SessionWindows.with(Duration.ofSeconds(4)))
  .count()

If events arrive at 2000ms, 5000ms, and 9000ms, how many session windows will be created?

A1

B2

C3

D0

Step-by-Step Solution

Solution:

Step 1: Understand session window gap
Session window inactivity gap is 4 seconds (4000ms).
Step 2: Analyze event gaps
Gap between 2000ms and 5000ms is 3000ms < 4000ms, so same session.
Gap between 5000ms and 9000ms is 4000ms, equals gap, so new session starts.
Final Answer:
2 -> Option B
Quick Check:
Session windows split when gap ≥ inactivity gap [OK]

Quick Trick: Session windows split if gap ≥ inactivity gap [OK]

Common Mistakes:

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