[Solved] You attempt to compile the following Kafka Streams code:stream1.join(stream2, (v1, v2) -> v1 + v2);but it fails. What is the most probable reason? | Kafka

Kafka - Streams

You attempt to compile the following Kafka Streams code:

stream1.join(stream2, (v1, v2) -> v1 + v2);

but it fails. What is the most probable reason?

AThe streams must have different key types to join successfully.

BThe join method is missing a Serde configuration for the key.

CThe value joiner function must return a boolean, not a concatenated string.

DThe join requires a window specification when joining two KStreams.

Step-by-Step Solution

Solution:

Step 1: Identify join type
Joining two KStreams requires specifying a window to define the time range for matching records.
Step 2: Check code
The code lacks a window parameter, causing compilation failure.
Final Answer:
A -> Option D
Quick Check:
KStream-KStream join needs a window [OK]

Quick Trick: KStream-KStream join must specify a window [OK]

Common Mistakes:

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