[Solved] What will be the output of this Java code?class Animal { void sound() { System.out.println("Animal sound"); } } class Dog extends Animal { void sound() { System.out.println("Bark");... | Java

Java - Polymorphism

What will be the output of this Java code?

class Animal { void sound() { System.out.println("Animal sound"); } } class Dog extends Animal { void sound() { System.out.println("Bark"); } } public class Test { public static void main(String[] args) { Animal a = new Dog(); a.sound(); } }

AAnimal sound

BRuntime error

CCompilation error

DBark

Step-by-Step Solution

Solution:

Step 1: Understand object type and method call
Variable 'a' is declared as Animal but refers to a Dog object. Method sound() is overridden in Dog.
Step 2: Determine which method runs
At runtime, Java calls Dog's sound() because of polymorphism (dynamic method dispatch).
Final Answer:
Bark -> Option D
Quick Check:
Polymorphism calls subclass method at runtime [OK]

Quick Trick: Reference type can be parent, object type decides method [OK]

Common Mistakes:

Expecting superclass method to run
Confusing compile-time and runtime method binding
Thinking this causes errors

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More Java Quizzes

What will be the output of this Java code?

Step 1: Understand object type and method call

Step 2: Determine which method runs

Final Answer:

Quick Check:

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