[Solved] Find the error in this code snippet:try { int[] arr = new int[3]; arr[5] = 10; } catch (ArrayIndexOutOfBoundsException e) { System.out.println("Index error"); } | Java

Java - Exception Handling

Find the error in this code snippet:

try {
  int[] arr = new int[3];
  arr[5] = 10;
} catch (ArrayIndexOutOfBoundsException e) {
  System.out.println("Index error");
}

AArray size is too small

BNo error, code runs fine

CCatch block syntax is wrong

DException type is incorrect

Step-by-Step Solution

Solution:

Step 1: Analyze array usage
Array declared with size 3, valid indices are 0,1,2; index 5 is out of bounds.
Step 2: Understand exception thrown
Accessing index 5 causes ArrayIndexOutOfBoundsException, which is correctly caught.
Final Answer:
Array size is too small -> Option A
Quick Check:
Index 5 invalid for size 3 = C [OK]

Quick Trick: Check array size vs accessed index to find error [OK]

Common Mistakes:

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