[Solved] Identify the error in the following code snippet:public class Example { public static void main(String[] args) { throw new Exception("Problem"); } } | Java

Java - Exception Handling

Identify the error in the following code snippet:

public class Example {
    public static void main(String[] args) {
        throw new Exception("Problem");
    }
}

AMissing try-catch block or throws declaration for checked exception.

BIncorrect exception message format.

CCannot throw exceptions in main method.

DException class does not exist.

Step-by-Step Solution

Solution:

Step 1: Identify exception type
The code throws Exception, which is a checked exception in Java.
Step 2: Check handling of checked exceptions
Checked exceptions must be either caught in a try-catch block or declared with throws in the method signature. This code does neither, causing a compile error.
Final Answer:
Missing try-catch block or throws declaration for checked exception. -> Option A
Quick Check:
Checked exceptions need handling = D [OK]

Quick Trick: Checked exceptions require try-catch or throws declaration [OK]

Common Mistakes:

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