[Solved] What will be the output of this code?try { int a = 5 / 0; } catch (ArithmeticException e) { System.out.println("Arithmetic Exception caught"); } catch (Exception e) { System.out.... | Java

Java - Exception Handling

What will be the output of this code?

try {
  int a = 5 / 0;
} catch (ArithmeticException e) {
  System.out.println("Arithmetic Exception caught");
} catch (Exception e) {
  System.out.println("General Exception caught");
}

ANo output

BArithmetic Exception caught

CGeneral Exception caught

DCompilation error

Step-by-Step Solution

Solution:

Step 1: Identify exception thrown
Division by zero throws ArithmeticException.
Step 2: Determine which catch block handles it
The first catch block matches ArithmeticException, so it runs.
Final Answer:
Arithmetic Exception caught -> Option B
Quick Check:
Specific catch handles matching exception first [OK]

Quick Trick: Specific exceptions caught before general ones [OK]

Common Mistakes:

Assuming general Exception catch runs first
Thinking division by zero causes compile error
Ignoring exception type matching

Master "Exception Handling" in Java

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More Java Quizzes

What will be the output of this code?

Step 1: Identify exception thrown

Step 2: Determine which catch block handles it

Final Answer:

Quick Check:

Want More Practice?