Solution:Step 1: Understand variable shadowing in increment()Inside increment(), a local variable 'count' is declared and set to 5, then incremented to 6. This does not affect the instance variable.Step 2: Check what getCount() returnsgetCount() returns the instance variable 'count', which remains 0

[Solved] Consider this class:class Counter { int count = 0; public void increment() { int count = 5; count++;... } }What will getCount() return after calling increment() once? | Java

Java - Classes and Objects

Consider this class:

class Counter {
  int count = 0;
  public void increment() {
    int count = 5;
    count++;
  }
  public int getCount() {
    return count;
  }
}

What will getCount() return after calling increment() once?

A1

B0

C5

D6

Step-by-Step Solution

Solution:

Step 1: Understand variable shadowing in increment()
Inside increment(), a local variable 'count' is declared and set to 5, then incremented to 6. This does not affect the instance variable.
Step 2: Check what getCount() returns
getCount() returns the instance variable 'count', which remains 0 because increment() did not change it.
Final Answer:
0 -> Option B
Quick Check:
Local variable shadows instance variable, instance unchanged [OK]

Quick Trick: Local variables hide instance variables inside methods. [OK]

Common Mistakes:

Assuming instance variable changes when local variable changes.
Confusing local and instance variable scopes.
Expecting incremented value to affect instance variable.

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Consider this class:

Step 1: Understand variable shadowing in increment()

Step 2: Check what getCount() returns

Final Answer:

Quick Check:

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