[Solved] Given the code below, what will be the output?String s1 = "Java";String s2 = new String("Java");String s3 = s2.intern();System.out.println(s1 == s2);System.out.println(s1 == s3);Why does this happen? | Java

Java - Strings and String Handling

Given the code below, what will be the output?

String s1 = "Java";
String s2 = new String("Java");
String s3 = s2.intern();
System.out.println(s1 == s2);
System.out.println(s1 == s3);

Why does this happen?

Afalse false - all are different objects

Btrue false - new String creates pooled string

Cfalse true - intern() returns the pooled string reference

Dtrue true - all strings are pooled automatically

Step-by-Step Solution

Solution:

Step 1: Analyze s1 and s2 references
s1 is a string literal in the pool, s2 is a new String object outside the pool, so s1 == s2 is false.
Step 2: Understand intern() method effect
s3 = s2.intern() returns the reference from the string pool for "Java", which is the same as s1, so s1 == s3 is true.
Final Answer:
false true - intern() returns the pooled string reference -> Option C
Quick Check:
intern() returns pool reference [OK]

Quick Trick: intern() returns pooled string reference [OK]

Common Mistakes:

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