[Solved] What will be the output of this Java code?class Demo { static int x; static { x = 10; System.out.print(x + " "); } public static void main(String[] args) { System.out.print(x); } } | Java

Java - Static Keyword

What will be the output of this Java code?

class Demo {
  static int x;
  static {
    x = 10;
    System.out.print(x + " ");
  }
  public static void main(String[] args) {
    System.out.print(x);
  }
}

ACompilation error

B0 10

C10 0

D10 10

Step-by-Step Solution

Solution:

Step 1: Trace static block execution
The static block runs first, sets x=10, and prints "10 ".
Step 2: Trace main method execution
Main method prints x which is 10, so output continues as "10".
Final Answer:
10 10 -> Option D
Quick Check:
Static block runs first, then main prints updated x [OK]

Quick Trick: Static block runs before main, initializes static variables [OK]

Common Mistakes:

Assuming static variables default to 0 after static block
Thinking static block runs after main
Confusing output order

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What will be the output of this Java code?

Step 1: Trace static block execution

Step 2: Trace main method execution

Final Answer:

Quick Check:

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