You want to safely parse a String input to an int in Java, returning -1 if the input is not a valid number. Which code snippet correctly implements this?

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Java - Command Line Arguments

You want to safely parse a String input to an int in Java, returning -1 if the input is not a valid number. Which code snippet correctly implements this?

Aint parseSafe(String s) { try { return Integer.parseInt(s); } catch (NumberFormatException e) { return -1; } }

Bint parseSafe(String s) { return Integer.parseInt(s); }

Cint parseSafe(String s) { if (s.matches("\\d+")) return Integer.parseInt(s); else return 0; }

Dint parseSafe(String s) { return Integer.valueOf(s); }

Step-by-Step Solution

Solution:

Step 1: Understand safe parsing with exception handling
Using try-catch around Integer.parseInt catches invalid input and returns fallback.
Step 2: Check each option's behavior
The snippet with try-catch returns parsed int or -1 on error. Snippets without proper handling throw exceptions, return 0 instead of -1, or use valueOf which returns an Integer object not int.
Final Answer:
The try-catch code returning -1 on NumberFormatException -> Option A
Quick Check:
Try-catch with -1 fallback handles invalid input [OK]

Quick Trick: Use try-catch to handle invalid input safely [OK]

Common Mistakes:

Not handling NumberFormatException
Returning wrong fallback value
Confusing Integer.valueOf with parseInt

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You want to safely parse a String input to an int in Java, returning -1 if the input is not a valid number. Which code snippet correctly implements this?

Step 1: Understand safe parsing with exception handling

Step 2: Check each option's behavior

Final Answer:

Quick Check:

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