Which Swift code snippet correctly runs two async tasks concurrently and waits for both results before proceeding?

hard📝 Application Q9 of 15

iOS Swift - Concurrency

Alet first = await fetchFirst() let second = await fetchSecond() print(first, second)

Basync let first = fetchFirst() async let second = fetchSecond() let results = await (first, second)

CTask { let first = fetchFirst() let second = fetchSecond() print(await first, await second) }

Dlet first = fetchFirst() let second = fetchSecond() print(first, second)

Step-by-Step Solution

Solution:

Step 1: Understand concurrency with async let
Using async let starts tasks concurrently without waiting immediately.
Step 2: Await tuple of results
Awaiting the tuple (first, second) waits for both tasks to complete.
Step 3: Analyze other options
let first = await fetchFirst() let second = await fetchSecond() print(first, second) runs tasks sequentially; C incorrectly mixes Task and awaits; D does not await at all.
Final Answer:
async let first = fetchFirst() async let second = fetchSecond() let results = await (first, second) -> Option B
Quick Check:
Use async let for concurrency, await tuple for results [OK]

Quick Trick: Use async let to start tasks concurrently [OK]

Common Mistakes:

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