[Solved] How do you correctly create a Task in Swift that asynchronously returns the integer 42? — Ans: let task = Task { return 42 } | iOS Swift

iOS Swift - Concurrency

How do you correctly create a Task in Swift that asynchronously returns the integer 42?

Alet task = Task.async { return 42 }

Blet task = Task<Int> { print(42) }

Clet task = Task.run { 42 }

Dlet task = Task { return 42 }

Step-by-Step Solution

Solution:

Step 1: Understand Task creation syntax
In Swift concurrency, a Task is created using Task { ... } with a closure that returns the desired value asynchronously.
Step 2: Analyze options
let task = Task { return 42 } correctly uses Task { return 42 }. let task = Task { print(42) } incorrectly uses Task and prints instead of returning. let task = Task.run { 42 } uses a non-existent Task.run method. let task = Task.async { return 42 } uses Task.async which is invalid.
Final Answer:
let task = Task { return 42 } -> Option D
Quick Check:
Task creation uses Task { ... } syntax [OK]

Quick Trick: Use Task { } with a closure returning the value [OK]

Common Mistakes:

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How do you correctly create a Task in Swift that asynchronously returns the integer 42?