[Solved] What is the issue with this Swift code using structured concurrency?func loadStrings() async { let group = withTaskGroup(of: String.self) { group in group.addTask { "Swift" } } print(await group.... | iOS Swift

iOS Swift - Concurrency

What is the issue with this Swift code using structured concurrency?

func loadStrings() async {
  let group = withTaskGroup(of: String.self) { group in
    group.addTask { "Swift" }
  }
  print(await group.next())
}

AThe group variable is not awaited and does not return a TaskGroup instance

BThe addTask closure must be marked async

Cgroup.next() cannot be awaited inside the function

DThe function must return a value

Step-by-Step Solution

Solution:

Step 1: Understand withTaskGroup return type
The withTaskGroup function is async and returns the result of its closure, not a TaskGroup instance.
Step 2: Analyze the code
Assigning let group = withTaskGroup {} is incorrect because group is not a TaskGroup but the closure's return value.
Step 3: Correct usage
Use await withTaskGroup and handle the group inside the closure; do not assign it to a variable.
Final Answer:
The group variable is not awaited and does not represent a TaskGroup instance -> Option A
Quick Check:
withTaskGroup returns closure result, not a TaskGroup object [OK]

Quick Trick: withTaskGroup returns closure result, not a TaskGroup instance [OK]

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