[Solved] You have an array of dictionaries representing people: let people = [ ["name": "John", "age": 30], ["name": "Alice", "age": 25], ["name": "Bob", "age": 30], ["name": "Carol", "age":... | iOS Swift

iOS Swift - Local Data Persistence

You have an array of dictionaries representing people:

let people = [
  ["name": "John", "age": 30],
  ["name": "Alice", "age": 25],
  ["name": "Bob", "age": 30],
  ["name": "Carol", "age": 25]
]

How do you filter for people aged 25 and sort them by name ascending using NSPredicate and Swift sorting?

AUse NSPredicate(format: "age = 25") and sort with sorted(by: { $0["name"]! > $1["name"]! })

BUse NSPredicate(format: "age >= 25") and sort with sorted(by: { $0["age"]! < $1["age"]! })

CUse NSPredicate(format: "age == 25") and sort with sorted(by: { $0["name"]! < $1["name"]! })

DUse NSPredicate(format: "age == '25'") and sort with sorted(by: { $0["name"]! < $1["name"]! })

Step-by-Step Solution

Solution:

Step 1: Write correct NSPredicate for age 25
Use "age == 25" to filter exactly age 25; single equals is invalid.
Step 2: Sort filtered array by name ascending
Sort by comparing names with < operator for ascending order.
Final Answer:
Use NSPredicate(format: "age == 25") and sort with sorted(by: { $0["name"]! < $1["name"]! }) -> Option C
Quick Check:
Filter age == 25, sort by name ascending [OK]

Quick Trick: Use == for equality and < for ascending sort [OK]

Common Mistakes:

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