[Solved] Given the struct below, which SwiftUI code correctly displays a list of User... Given the struct below, which SwiftUI code correctly displays a list of User instances using ForEach inside a List? | iOS Swift

iOS Swift - Lists and Data Display

Given the struct below, which SwiftUI code correctly displays a list of User instances using ForEach inside a List?

struct User: Identifiable {
  let id: UUID
  let username: String
}

let users = [User(id: UUID(), username: "john"), User(id: UUID(), username: "jane")]

AList { ForEach(users) { Text($0.username) } }

BList { ForEach(users, id: \.username) { user in Text(user.username) } }

CList { ForEach(users, id: \.id) { user in Text(user.username) } }

DList { ForEach(users) { user in Text(user.username) } }

Step-by-Step Solution

Solution:

Step 1: Check Identifiable conformance
The User struct conforms to Identifiable via id property.
Step 2: ForEach usage
When data conforms to Identifiable, ForEach can be used without specifying an id.
Step 3: Analyze options
List { ForEach(users) { user in Text(user.username) } } correctly uses ForEach(users). List { ForEach(users, id: \.username) { user in Text(user.username) } } incorrectly uses username as id. List { ForEach(users, id: \.id) { user in Text(user.username) } } is redundant but valid. List { ForEach(users) { Text($0.username) } } uses shorthand but is less clear.
Final Answer:
List { ForEach(users) { user in Text(user.username) } } -> Option D
Quick Check:
Use ForEach with Identifiable data without id param [OK]

Quick Trick: Use ForEach with Identifiable data without id param [OK]

Common Mistakes:

Specifying id when Identifiable is already conformed
Using non-unique properties as id

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More iOS Swift Quizzes

Given the struct below, which SwiftUI code correctly displays a list of User instances using ForEach inside a List?

Step 1: Check Identifiable conformance

Step 2: ForEach usage

Step 3: Analyze options

Final Answer:

Quick Check:

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