[Solved] What will be printed by this Swift code?func fetchNumber() async -> Int { return 42 } Task { let number = await fetchNumber() print(number) } | iOS Swift

iOS Swift - Concurrency

What will be printed by this Swift code?

func fetchNumber() async -> Int {
  return 42
}

Task {
  let number = await fetchNumber()
  print(number)
}

A42

Bnil

CTask

DCompilation error

Step-by-Step Solution

Solution:

Step 1: Understand async function return
The async function fetchNumber() returns 42 as an Int.
Step 2: Await call inside Task and print
The await keyword waits for the async function to finish, then prints 42.
Final Answer:
42 -> Option A
Quick Check:
Await fetch returns 42 printed = D [OK]

Quick Trick: Await pauses until async returns value [OK]

Common Mistakes:

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