[Solved] What is wrong with this Swift code snippet? let number: Int? = 10 let result: Int = number print(result) | iOS Swift

iOS Swift - Swift Language Essentials

What is wrong with this Swift code snippet?

let number: Int? = 10
let result: Int = number
print(result)

AOptional Int cannot hold a value

Bprint statement cannot print Int values

CCannot assign optional Int to non-optional Int without unwrapping

DVariable 'result' should be declared as optional

Step-by-Step Solution

Solution:

Step 1: Identify type mismatch
number is an optional Int, result is a non-optional Int.
Step 2: Understand unwrapping requirement
You must unwrap optionals before assigning to non-optional variables.
Final Answer:
Cannot assign optional Int to non-optional Int without unwrapping -> Cannot assign optional Int to non-optional Int without unwrapping
Quick Check:
Optionals require unwrapping before assignment [OK]

Quick Trick: Unwrap optionals before assigning to non-optionals [OK]

Common Mistakes:

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