[Solved] Identify the error in this Swift code snippet targeting premium users: func greetUser(isPremium: Bool) { if isPremium = true { print("Thanks for being premium!") } else { print("Welcome!") } } | iOS Swift

iOS Swift - iOS Basics and Setup

Identify the error in this Swift code snippet targeting premium users:

func greetUser(isPremium: Bool) {
  if isPremium = true {
    print("Thanks for being premium!")
  } else {
    print("Welcome!")
  }
}

AMissing return type in function

BIncorrect print statement syntax

CUsing '=' instead of '==' in the if condition

DFunction name should be capitalized

Step-by-Step Solution

Solution:

Step 1: Check the if condition syntax
The condition uses '=' which is assignment, not comparison. It should be '==' to compare values.
Step 2: Verify other syntax elements
Function return type is optional for Void, print syntax is correct, and function naming conventions allow lowercase.
Final Answer:
Using '=' instead of '==' in the if condition -> Option C
Quick Check:
Comparison needs '==' not '=' [OK]

Quick Trick: Use '==' for comparison, '=' is assignment [OK]

Common Mistakes:

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Identify the error in this Swift code snippet targeting premium users: