[Solved] What will be printed by this Swift code?var score: Int? = 85 if let safeScore = score { print("Score is \(safeScore)") } else { print("No score") } | iOS Swift

iOS Swift - Swift Language Essentials

What will be printed by this Swift code?

var score: Int? = 85
if let safeScore = score {
  print("Score is \(safeScore)")
} else {
  print("No score")
}

AScore is 85

BNo score

COptional(85)

DError: score is Optional

Step-by-Step Solution

Solution:

Step 1: Understand Optional value
Variable score holds Optional Int with value 85.
Step 2: Analyze if let unwrapping
The if let safeScore = score unwraps the value 85 successfully, so the print inside if runs.
Final Answer:
Score is 85 -> Option A
Quick Check:
Unwrapped Optional prints value, not nil or error [OK]

Quick Trick: If Optional has value, if let unwrap runs [OK]

Common Mistakes:

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