[Solved] Which of the following is the correct syntax to safely unwrap an Optional age: Int? using if let? — Ans: if let unwrappedAge = age { print(unwrappedAge) } | iOS Swift

iOS Swift - Swift Language Essentials

Which of the following is the correct syntax to safely unwrap an Optional age: Int? using if let?

Aif let unwrappedAge = age { print(unwrappedAge) }

Bif age != nil { print(age) }

Cif let age = age? { print(age) }

Dif age = nil { print(age) }

Step-by-Step Solution

Solution:

Step 1: Recall safe unwrapping syntax
Safe unwrapping uses if let to bind the Optional value if it exists.
Step 2: Check each option
if let unwrappedAge = age { print(unwrappedAge) } correctly unwraps with if let unwrappedAge = age. if age != nil { print(age) } checks nil but does not unwrap. if let age = age? { print(age) } has invalid syntax with age?. if age = nil { print(age) } wrongly assigns nil in condition.
Final Answer:
if let unwrappedAge = age { print(unwrappedAge) } -> Option A
Quick Check:
Safe unwrap = if let variable = optional [OK]

Quick Trick: Use if let variable = optional to unwrap safely [OK]

Common Mistakes:

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Which of the following is the correct syntax to safely unwrap an Optional age: Int? using if let?