[Solved] What output is produced when this Swift code runs after the keyboard appears?NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillHide), name: UIResponder.... | iOS Swift

iOS Swift - User Input and Forms

What output is produced when this Swift code runs after the keyboard appears?

NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillHide), name: UIResponder.keyboardWillHideNotification, object: nil)

@objc func keyboardWillHide(notification: Notification) {
  print("Keyboard is hiding")
}

APrints "Keyboard is hiding" when keyboard appears

BPrints "Keyboard is hiding" when keyboard disappears

CNo output because observer is not added

DPrints "Keyboard is showing" when keyboard appears

Step-by-Step Solution

Solution:

Step 1: Understand notification
The observer listens for keyboardWillHideNotification, triggered when keyboard is about to hide.
Step 2: Analyze selector
The selector prints "Keyboard is hiding" when notification fires.
Final Answer:
Prints "Keyboard is hiding" when keyboard disappears -> Option B
Quick Check:
keyboardWillHideNotification triggers on keyboard dismissal [OK]

Quick Trick: keyboardWillHideNotification fires when keyboard hides [OK]

Common Mistakes:

Confusing keyboardWillShowNotification with keyboardWillHideNotification
Expecting output on keyboard appearance
Not adding observer properly

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More iOS Swift Quizzes

What output is produced when this Swift code runs after the keyboard appears?

Step 1: Understand notification

Step 2: Analyze selector

Final Answer:

Quick Check:

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