[Solved] Identify the error in this SwiftUI grid code:LazyVGrid(rows: [GridItem(.fixed(100))]) { Text("One") Text("Two") Text("Three") } | iOS Swift

iOS Swift - SwiftUI Layout

Identify the error in this SwiftUI grid code:

LazyVGrid(rows: [GridItem(.fixed(100))]) {
  Text("One")
  Text("Two")
  Text("Three")
}

AGridItem should be .flexible() not .fixed()

BLazyVGrid requires columns parameter instead of rows

CMissing ForEach to iterate items

DText views cannot be direct children of LazyVGrid

Step-by-Step Solution

Solution:

Step 1: Check grid parameters
LazyVGrid accepts columns parameter, not rows.
Step 2: Eliminate other options
.fixed() is valid for GridItem; ForEach is not required for static views; Text views can be direct children.
Final Answer:
LazyVGrid requires columns parameter instead of rows -> Option B
Quick Check:
LazyVGrid = columns parameter [OK]

Quick Trick: LazyVGrid uses columns parameter, not rows [OK]

Common Mistakes:

Master "SwiftUI Layout" in iOS Swift

9 interactive learning modes - each teaches the same concept differently

More iOS Swift Quizzes

Identify the error in this SwiftUI grid code: