[Solved] You want to create a grid with 3 columns where the first column is fixed width 100, the second is flexible, and the third is adaptive... Which code correctly defines the columns array for LazyVGrid? | iOS Swift

iOS Swift - SwiftUI Layout

You want to create a grid with 3 columns where the first column is fixed width 100, the second is flexible, and the third is adaptive with minimum 80 width. Which code correctly defines the columns array for LazyVGrid?

A[GridItem(.adaptive(minimum: 80)), GridItem(.fixed(100)), GridItem(.flexible())]

B[GridItem(.flexible()), GridItem(.fixed(100)), GridItem(.adaptive(minimum: 80))]

C[GridItem(.fixed(100)), GridItem(.flexible()), GridItem(.adaptive(minimum: 80))]

D[GridItem(.fixed(100)), GridItem(.adaptive(minimum: 80)), GridItem(.flexible())]

Step-by-Step Solution

Solution:

Step 1: Match column order with requirements
The first column must be fixed width 100, second flexible, third adaptive minimum 80.
Step 2: Check each GridItem in options
[GridItem(.fixed(100)), GridItem(.flexible()), GridItem(.adaptive(minimum: 80))] matches order: fixed(100), flexible(), adaptive(minimum: 80).
Final Answer:
[GridItem(.fixed(100)), GridItem(.flexible()), GridItem(.adaptive(minimum: 80))] -> Option C
Quick Check:
Order and types must match requirements [OK]

Quick Trick: Order of GridItems matches column order [OK]

Common Mistakes:

Mixing order of GridItems
Using wrong GridItem types
Confusing adaptive with flexible

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Which code correctly defines the columns array for LazyVGrid?

Step 1: Match column order with requirements

Step 2: Check each GridItem in options

Final Answer:

Quick Check:

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