[Solved] Identify the error in this mutation definition:mutation deleteUser(id: ID!) { removeUser(id: id) { success } } | GraphQL

GraphQL - Mutations

Identify the error in this mutation definition:

mutation deleteUser(id: ID!) { removeUser(id: id) { success } }

AremoveUser field cannot have arguments

BVariable type ID! is incorrect

CMutation name deleteUser is invalid

DMissing $ before variable name in mutation definition

Step-by-Step Solution

Solution:

Step 1: Check variable declaration syntax
Variables in mutation definitions must start with $, e.g., $id: ID!.
Step 2: Verify usage inside mutation
Inside the mutation body, use the variable with $id, not just id.
Final Answer:
Missing $ before variable name in mutation definition -> Option D
Quick Check:
Variables require $ prefix in definition and usage [OK]

Quick Trick: Always prefix variables with $ in mutation definitions [OK]

Common Mistakes:

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