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How do you declare a field in a GraphQL schema that relies on the default resolver without explicitly defining a resolver function?

easy📝 Syntax Q3 of 15
GraphQL - Resolvers
How do you declare a field in a GraphQL schema that relies on the default resolver without explicitly defining a resolver function?
AUse the @default directive on the field definition.
BAdd a resolver that returns null for the field.
CSimply define the field with its type in the schema without adding a resolver.
DDefine the field as a scalar type only.
Step-by-Step Solution
Solution:
  1. Step 1: Recall schema definition basics

    Fields in GraphQL schemas are defined with their names and types.
  2. Step 2: Understand default resolver usage

    If no resolver is provided, GraphQL uses the default resolver automatically.
  3. Step 3: Identify correct syntax

    Simply declaring the field and its type is sufficient to use the default resolver.
  4. Final Answer:

    Simply define the field with its type in the schema without adding a resolver. -> Option C
  5. Quick Check:

    Field declaration alone uses default resolver [OK]
Quick Trick: Field declaration alone uses default resolver [OK]
Common Mistakes:
  • Thinking a resolver function must be defined
  • Assuming @default directive exists
  • Believing scalar type restriction is needed

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