[Solved] Examine the following Flask code snippet:from flask import Flask import threading app = Flask(__name__) @app.route('/start') def start_task(): def task(): print('Task executed') threading.... | Flask

Flask - Background Tasks

Examine the following Flask code snippet:

from flask import Flask
import threading
app = Flask(__name__)

@app.route('/start')
def start_task():
    def task():
        print('Task executed')
    threading.Thread(target=task).run()
    return 'Task started'

What is the error in this code?

AMissing <code>app.run()</code> to start the Flask app

BDefining the task function inside the route handler

CUsing <code>run()</code> instead of <code>start()</code> to launch the thread

DNot returning a JSON response from the route

Step-by-Step Solution

Solution:

Step 1: Understand threading methods
The threading.Thread class has a start() method to begin execution in a new thread. The run() method runs the target function in the current thread synchronously.
Step 2: Identify the error
The code calls threading.Thread(target=task).run(), which executes task synchronously, blocking the request instead of running it in background.
Final Answer:
Using run() instead of start() to launch the thread -> Option C
Quick Check:
Check if start() is used to launch threads [OK]

Quick Trick: Always call start(), not run(), to start a new thread [OK]

Common Mistakes:

MISTAKES

Confusing run() with start() in threading
Thinking defining functions inside routes is an error
Expecting JSON response when plain string is acceptable

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More Flask Quizzes

Examine the following Flask code snippet:

Step 1: Understand threading methods

Step 2: Identify the error

Final Answer:

Quick Check:

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