[Solved] Identify the error in this Flask route for checking task status: @app.route('/status/<task_id>') def status(task_id): state = tasks[task_id] return {'task': task_id, 'status': state} | Flask

Flask - Background Tasks

Identify the error in this Flask route for checking task status:

@app.route('/status/<task_id>')
def status(task_id):
    state = tasks[task_id]
    return {'task': task_id, 'status': state}

AUsing tasks[task_id] without checking if key exists

BReturning a dictionary instead of JSON response

CMissing @app.route decorator

DIncorrect route URL syntax

Step-by-Step Solution

Solution:

Step 1: Analyze dictionary access
Accessing tasks[task_id] without checking key causes KeyError if missing.
Step 2: Confirm other parts are correct
Returning dict is allowed by Flask; decorator and route syntax are correct.
Final Answer:
Using tasks[task_id] without checking if key exists -> Option A
Quick Check:
Direct dict access risks KeyError [OK]

Quick Trick: Always check dict keys before access to avoid errors [OK]

Common Mistakes:

MISTAKES

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