[Solved] How do you correctly apply Werkzeug's ProfilerMiddleware to a Flask app instance named app? — Ans: app.wsgi_app = ProfilerMiddleware(app.wsgi_app) | Flask

Flask - Performance Optimization

How do you correctly apply Werkzeug's ProfilerMiddleware to a Flask app instance named app?

AProfilerMiddleware(app.wsgi_app)

Bapp = ProfilerMiddleware(app)

Capp.middleware = ProfilerMiddleware(app)

Dapp.wsgi_app = ProfilerMiddleware(app.wsgi_app)

Step-by-Step Solution

Solution:

Step 1: Understand Flask WSGI App
Flask's WSGI app is accessible via app.wsgi_app.
Step 2: Wrap WSGI App
ProfilerMiddleware wraps the WSGI app, so assign it back to app.wsgi_app.
Final Answer:
app.wsgi_app = ProfilerMiddleware(app.wsgi_app) -> Option D
Quick Check:
Middleware wraps app.wsgi_app, not app directly [OK]

Quick Trick: Wrap Flask's wsgi_app attribute with ProfilerMiddleware [OK]

Common Mistakes:

MISTAKES

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How do you correctly apply Werkzeug's ProfilerMiddleware to a Flask app instance named app?